I am trying to create a vector where I have 3 repetitions of the number 1, then 3 repetitions of the number 2, and so on up to, for instance, 3 repetitions of the number 36.
c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5...)
I have tried the following use of rep() but got the following error:
Error in rep(3, seq(1:36)) : argument 'times' incorrect
What formulation do I need to use to properly generate the vector I want?
CodePudding user response:
sort(rep(1:36, 3))
Or even better as @Wimpel mentioned in the comments, use the each argument of the rep function.
rep(1:36, each = 3)
output
# [1] 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 6 6 6 7 7 7 8 8 8 9 9 9 10 10 10 11 11 11 12 12 12 13 13 13 14 14 14 15 15 15 16 16 16 17 17 17 18 18 18 19 19 19 20 20 20 21 21 21 22
# [65] 22 22 23 23 23 24 24 24 25 25 25 26 26 26 27 27 27 28 28 28 29 29 29 30 30 30 31 31 31 32 32 32 33 33 33 34 34 34 35 35 35 36 36 36
CodePudding user response:
This one should work. However probably not the most elegant.
reps = c()
n = 36
for(i in 1:n){
reps = append(reps, rep(i, 3))
}
reps
alternatively using the rep function properly (see documentation (?rep
for argument each
):
rep(1:36,each = 3)
CodePudding user response:
rep
approach is preferable (see existing answers)
Here are some other options:
> kronecker(1:36, rep(1, 3))
[1] 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 6 6 6 7 7 7 8 8 8 9
[26] 9 9 10 10 10 11 11 11 12 12 12 13 13 13 14 14 14 15 15 15 16 16 16 17 17
[51] 17 18 18 18 19 19 19 20 20 20 21 21 21 22 22 22 23 23 23 24 24 24 25 25 25
[76] 26 26 26 27 27 27 28 28 28 29 29 29 30 30 30 31 31 31 32 32 32 33 33 33 34
[101] 34 34 35 35 35 36 36 36
> c(outer(rep(1, 3), 1:36))
[1] 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 6 6 6 7 7 7 8 8 8 9
[26] 9 9 10 10 10 11 11 11 12 12 12 13 13 13 14 14 14 15 15 15 16 16 16 17 17
[51] 17 18 18 18 19 19 19 20 20 20 21 21 21 22 22 22 23 23 23 24 24 24 25 25 25
[76] 26 26 26 27 27 27 28 28 28 29 29 29 30 30 30 31 31 31 32 32 32 33 33 33 34
[101] 34 34 35 35 35 36 36 36