free | grep Mem | awk '{print $4/$2 * 100.0}'

I want to remove the decimal places from this output.

CodePudding user response：

A couple observations:

1. No need for using grep as awk can handle that
2. Use printf instead of print to control the precision

free | awk '/Mem/ { percent = $4 / $2 * 100.0; printf "%0.0f\n", percent; }'

CodePudding user response：

1. Use awk /pattern/ to select the correct row.
2. Convert to integer to get rid of decimal points.

Code:

free | awk '/Mem/ { print int(100 * $4 / $2) }'

CodePudding user response：

free | grep Mem | awk '{print $4/$2 * 100.0}' | cut -d. -f1

or

free | grep Mem | awk '{print int($4/$2 * 100.0)}'

CodePudding user response：

You can convert to int in awk

free | awk '/^Mem/ { print int($4 * 100.0/$2) }'
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