Trying to iterate over lists and nested list to zip items into dictionary-CodePudding

I have two lists, one of them contains a view hundred nested lists. I want to combine items of both and zip them into a dict.

code example:

list1 = ['SYNNR', 'NAME', 'BUNDESLAND']
list2 = [['11032', 'POYSDORF-OST', 'NOE'], ['11033', 'POYSDORF-WEST', 'NOE'], ['11034', 'POYSDORF-NORD', 'NOE']]

#iterate and zip
for i in range(len(list2)):
    result = dict(zip(list1, list2[i]))
print(result)

result

{'SYNNR': '11034', 'NAME': 'POYSDORF-NORD', 'BUNDESLAND': 'NOE'}

Only the last list inside list2 gets zipped in the dict. but I need to get dict for every list inside list2, like this

{'SYNNR': '11032', 'NAME': 'POYSDORF-OST', 'BUNDESLAND': 'NOE'}, {'SYNNR': '11033', 'NAME': 'POYSDORF-WEST', 'BUNDESLAND': 'NOE'}, {'SYNNR': '11034', 'NAME': 'POYSDORF-NORD', 'BUNDESLAND': 'NOE'}

Thanks for ideas!!

CodePudding user response：

Your code only returns the last dict that you create. Perhaps, instead of a single dict, you wanted a list of dicts:

result = []
for i in range(len(list2)):
    result.append(dict(zip(list1, list2[i])))
print(result)

However, as usual, instead of using the range(len(... idiom you can express this directly as a list comprehension:

result = [dict(zip(list1, line)) for line in list2]

CodePudding user response：

The problem is that you are overwriting the result variable for every item in the list, instead, you should have an array of dictionaries for the result variable

#iterate and zip
result = []
for i in range(len(list2)):
    result.append(dict(zip(list1, list2[i])))
print(result)

Another, optional improvement you could do is to simplify the first for, that would improve readability

result = []
for item in list2:
    result.append(dict(zip(list1, item)))
print(result)