I have made several efforts to select a single specific document that contains the minimum value from the database.
let Lowestdate = await BTCMongo.aggregate(
[
// { "$sort": { "name": 1,
{
$match : { "createdAt" : { $gte: new Date(last),$lte: new Date(NEW) } } },
{
$group:
{
_id:null,
minFee_doc:{$min: "$$ROOT"},
minFee: { $min:{$toDouble:"$one"}},
firstFee: { $first: "$one" },
lastFee: { $last: "$one" },
maxFee: { $max: {$toDouble:"$one"}},
}
},
]
).then(result => {}):
with minFee_doc:{$min: "$$ROOT"},
I have been trying to return the document containing the minimum $min
but it keeps returning document containing $first
How do i select the document with minimum value?
Note : i will like to return the whole document including the "CreatedAt" "UpdatedAt", and _id. of the document containing the minimum value
Expected Result should look like:
{
"minFee_doc": {
"_id": "61e84c9f622642463640e05c",
"createdAt": "2022-01-19T17:38:39.034Z",
"updatedAt": "2022-04-24T14:48:38.100Z",
"__v": 0,
"one": 2
},
"minFee": 2,
"firstFee": 3,
"lastFee": 5,
"maxFee": 6
}
Edit: also to provide a single document not multiple
CodePudding user response:
$push
all docs in $group
then $set
the array with $filter
db.collection.aggregate([
{
$match: {}
},
{
$group: {
_id: null,
minFee_doc: { $push: "$$ROOT" },
minFee: { $min: { $toDouble: "$one" } },
firstFee: { $first: "$one" },
lastFee: { $last: "$one" },
maxFee: { $max: { $toDouble: "$one" } }
}
},
{
$set: {
minFee_doc: {
$filter: {
input: "$minFee_doc",
as: "m",
cond: { "$eq": [ "$$m.one", "$minFee" ] }
}
}
}
}
])