Can i create new object by define new keyword from object literal?-CodePudding

I have created an object by defining the 'new' keyword from the object literal. But the problem is I can't access that object without looping. so is there any way to access that object?

const animal = {
  animalDetails: function(a, b) {
    this.a = a
    this.b = b
  },

  animalOutPut: function() {
    console.log(this.a, this.b)
  },
}

// passing output by parameter ................................................................

animal.animalDetails('ape', 'Baboon')

// Call the object animal ................................................................

animal.animalOutPut()

// Create New Object Fruits from animal object literal ................................................................
let fruits = new animal.animalDetails('Apple', 'Blackberries')


for (let v in fruits) {
  console.log(fruits[v])
}

CodePudding user response：

You want a class

class animal {

  constructor(a, b){

    this.a = a;
    this.b = b;
 
  }

  animalOutput(){

    console.log(this.a, this.b);

  }

}

You can easily define the class let tiger = new animal("tiger", "grrr") A class allows you to create multiple of them as well, much more useful then an object.

Hope this helped!

CodePudding user response：

You don't need to loop it. You can access the a and b properties just like you can with animal.

You can't use fruits.animalOutput() because animalOutput is a property only of the animal object. This object is not a prototype of objects created using new animalDetails(), so there's no inheritance.

const animal = {
  animalDetails: function(a, b) {
    this.a = a
    this.b = b
  },

  animalOutPut: function() {
    console.log(this.a, this.b)
  },
}

// passing output by parameter ................................................................

animal.animalDetails('ape', 'Baboon')

// Call the object animal ................................................................

animal.animalOutPut()

// Create New Object Fruits from animal object literal ................................................................
let fruits = new animal.animalDetails('Apple', 'Blackberries')

console.log(fruits.a, fruits.b);