Python how to use .pack for an other monitor resolution?-CodePudding

Hi i can't solve this problem, i created a program in a 1920x1080 resolution monitor and when i run it on purpose on an other pc with 1366x768 resolution the position of the Labels is different, i picked the height that should be 768 in one case and 1080 in the other case with:

larghezza = window.winfo_screenheight()

and used in the pack placements:

bottone_reset.pack(side=BOTTOM,anchor=S,pady=(0,altezza*0.1))
bottone_premi.pack(side=BOTTOM,anchor=S,pady=(0,altezza*0.2))
etichetta_click.pack(side=BOTTOM,anchor=S,pady=(0,altezza*0.1))
etichetta_titolo.pack(side=BOTTOM,anchor=S,pady=(0,altezza*0.1))

Because in this way the formula changes according to the current monitor resolution but the Labels are still in a different position, how to handle this ? Thanks

CodePudding user response：

So, the problem being that the location of the buttons and label changes based on window size. You're trying to modify the positioning manually based on the window size. While ingenious, it's obviously not working as you intend. There are, however, different options other than pack(). These are grid() and place(). (Links go to "geeksforgeeks" website, which is what I'm currently using as reference.)

'grid()' places elements in a grid using columns and rows, and is best used for elements that have the same dimensions (at least in the direction you're placing them, so if you want them all aligned on the X direction, they should have similar length to not look weird).

bottone_reset.grid(column = 0, row = 0, padx = 5, pady = 5)
bottone_premi.grid(column = 1, row = 0, padx = 5, pady = 5)
etichetta_click.grid(column = 2, row = 0, padx = 5, pady = 5)
etichetta_titolo.grid(column = 3, row = 0, padx = 5, pady = 5)

'place()' lets you determine the explicit location of something, which can be useful but in case of your choice of element placement would likely not help, since if the window shortens, place will not change location.

I would suggest creating a frame for the elements listed, then depending on what is most useful to you, use pack() or grid() to place the elements within that frame. In turn, place that frame where you want the buttons to end up.

frame.pack(side=BOTTOM, anchor = S)

bottone_reset = Button(frame,text = "reset")
bottone_premi = Button(frame, text = "premi")
etichetta_click = Label(frame, text = "click")
etichetta_titolo = Label(frame, text = "Title")

Ofc, your definition of the buttons and labels will look different, these are just placeholders.

The following code will always place the buttons in the bottom center of the window, regardless of what size that screen is (unless the total elements no longer fit). It's closest to what I could see you were trying to attempt. of course, you'll have to replace my manual input of window width and height with your screen size detection. I could not immediately get that to work with just tkinter, so I decided to change values manually.

from tkinter import *

window = Tk()
window.title("Pack Problem")

windowWidth = 1000
windowHeight = 768
windowSize = str(windowWidth)   "x"   str(windowHeight)
window.geometry(windowSize)

frame = Frame()
frame.pack(side=BOTTOM, anchor = S)

bottone_reset = Button(frame,text = "reset")
bottone_premi = Button(frame, text = "premi")
etichetta_click = Label(frame, text = "click")
etichetta_titolo = Label(frame, text = "Title")

bottone_reset.grid(column = 0, row = 0, padx = 5, pady = 5)
bottone_premi.grid(column = 1, row = 0, padx = 5, pady = 5)
etichetta_click.grid(column = 2, row = 0, padx = 5, pady = 5)
etichetta_titolo.grid(column = 3, row = 0, padx = 5, pady = 5)


window.mainloop()

The layout and makeup are obviously just placeholders, but this should function as a framework for what you want to do.