So i make a turn based dos game, And i have a switch() function which gives me a bug.. :

int hp;
int mana;
do
{
    cout<<"Enter your arg here";
    cin>>choice;
    cout<<"Hahaha that won't stop me";
    switch(choice)
    {
      case 1:
        mana--;
        mana--;
        hp--;
        hp--;
        cout<<"Woosh";
    }
}
while(1)
{
  cout<<endl;
}

Ok so let me explain the bug :

1. When the player inputs choice variable it will just skip the switch() function an just go continue with cout<<"Hahaha that won't stop me";. How do i fix that? PS : Sorry for my bad english, and if there is a misswriting on this post. I'm so sorry about that.

CodePudding user response：

First of all, switch is not a function, it's a statement. That means, it doesn't behave like functions. What you've written here doesn't match with what you want. What the program does is:

1. printing the first line
2. reading the input
3. printing the second line
4. switching on the input

What you want is:

1. printing the first line
2. reading the input
3. switching on the input
4. printing the second line on default case

So let's reorder your code.

cout << "Enter your arg here";
cin >> choice;
switch (choice)
{
  case 1:
    mana -= 2;
    hp -= 2;
    cout << "Woosh";
    break;
  default:
    cout << "Hahaha that won't stop me";
    break;
}

And don't forget to write break; on every case, including default one.

CodePudding user response：

First of all, switch is not a function, it is a statement: it is basically a bunch of if == statements combined. So, what your switch statement is equivalent to:

if(choice==1)
{
   mana-=2;
   hp-=2;
   cout << "Whoosh!";
}

So, your code is not working, because it will only print "Whoosh!" if you type the number 1.

Also, you should know, that x-- is equivalent to x-=1 which is equivalent to x=x-1. So, instead of writing mana--;mana--;, you can write x-=2;.

It would be very helpful if you could include more of your code, for us to better understand your problem.