Firebase Storage Image upload - Function to return the Image URL after uploading it-CodePudding

I need to implement this async function,

const uploadImage = async () => {
  const filename = new Date().getTime()   photo!.name
  const storage = getStorage(app)
  const storageRef = ref(storage, filename)
  const uploadTask = uploadBytesResumable(storageRef, photo!);
  
  uploadTask.on('state_changed',
    (snapshot) => {},
    (error) => {
      console.log("error while uploading photo", error)
    },
    async () => {
      photoUrl = await getDownloadURL(uploadTask.snapshot.ref);
      console.log("getDownloadURL", photoUrl)
      return photoUrl
    }
  );
}

It is the function to upload images to Firebase-Storage. Here I need to return the "photoUrl ". I need to call the function like,

const res = await uploadImage(photo)

how do I do this? The uploaded image's URL should return from the function.

CodePudding user response：

The object returned by uploadBytesResumable is also a promise, so you can just await that and then call getDownloadURL:

const uploadImage = async () => {
  const filename = new Date().getTime()   photo!.name
  const storage = getStorage(app)
  const storageRef = ref(storage, filename)
  const uploadTask = uploadBytesResumable(storageRef, photo!);
  await uploadTask;
  photoUrl = await getDownloadURL(uploadTask.snapshot.ref);
  return photoUrl
}

You actually don't even need a reference to the task, as you already have the storageRef, the above can be shorted to:

const uploadImage = async () => {
  const filename = new Date().getTime()   photo!.name
  const storage = getStorage(app)
  const storageRef = ref(storage, filename)
  await uploadBytesResumable(storageRef, photo!);
  return await getDownloadURL(storageRef);
}