Change all occurance of password in propertie file in Bash-CodePudding

I would like to change all password in a file in a command and i'm stuck with my sed, i don't know how i can tell it to take the output of the sed

the example in my propeties file is like this:

username: testUsername
password: testPassword <--- passwords i want to be change

Here's what i got:

grep "password" application.yml | cut -d ":" -f2 | xargs -I pass sed -ie 's,'"$(pass)"',test,g' "app2"

and here's my output:

sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression

Thanks very much for your attention,

Florian

CodePudding user response：

With GNU sed:

pass="new_password"
sed -i -E 's/(password: ).*/\1'"$pass"'/' application.yml

Output to application.yml:

username: testUsername
password: new_password

The new password must not contain /.

See: The Stack Overflow Regular Expressions FAQ

CodePudding user response：

Using sed, match only lines that begin with password to carry out the substitution on.

-i.bak will create a backup of the file while saving the original file in place

$ sed -i.bak '/^password/s/ .*/ newPassword/' input_file
username: testUsername
password: newPassword