JavaScript: How can I do something like `throw new Error()`, but without logging it in the console a-CodePudding

throw new Error() logs an error and stops the running file, right? I want to do something similar to throwing error, but I want the file to still keep running, like if you do normal console.log. How can I achieve that?

CodePudding user response：

You can use a try...catch statement. If the code in the try block throws an exception then the code in the catch block will be executed. Then execution continues on afterwards.

let somethingElse = function() {
  alert('something else')
}

try {
  nonExistentFunction();
} catch (error) {
  console.error(error);
  // expected output: ReferenceError: nonExistentFunction is not defined
  // Note - error messages will vary depending on browser
  somethingElse()
}

console.log('after')

CodePudding user response：

You have to wrap the entire main function inside a try catch block:

function main() { ... }

try {
  main();
} catch (error) {
  console.error('There was a critical error while running the app');
  console.error(error);
}