Filter one dictionary out of list of dictionaries and extract values of certain keys-CodePudding

Objective: To filter out of list of dictionaries and extract specific values in that dictionary using python 3.x

Code:

output = data.decode("utf-8")
input = json.loads(output)
for itm in input['items']:
    print(itm)

The above code output:

{'name': 'ufg', 'id': '0126ffc8-a1b1-423e-b7fe-56d4e93a80d6', 'created_at': '2022-06-16T04:37:32.958Z'}
{'name': 'xyz', 'id': '194ac74b-54ac-45c6-b4d3-c3ae3ebc1d27', 'created_at': '2022-06-26T10:32:50.307Z'}
{'name': 'defg', 'id': '3744bdaa-4e74-46f6-bccb-1dc2eca2d2c1', 'created_at': '2022-06-26T10:55:21.273Z'}
{'name': 'abcd', 'id': '41541893-f916-426b-b135-c7500759b0b3', 'created_at': '2022-06-24T08:39:39.806Z'}

Now Need to filter only as output for example, I want only dictionary with 'name' as 'abcd'

expected filtered output:

{'name': 'abcd', 'id': '41541893-f916-426b-b135-c7500759b0b3', 'created_at': '2022-06-24T08:39:39.806Z'}

Now, I need to extract only 'name' and 'id' for this 'abcd' into python variable to use it next part of program

Please suggest.

CodePudding user response：

For your situation probably converting into dictionary then filtering would be best.

for itm in input['items']:
    itm = dict(itm)
    if(itm["name"] == "abcd"):
        print(itm["name"],itm["id"])

however, if itm = dict(itm) wouldn't work for your situation, you can use json.loads(itm) then itm = dict(itm).