My browse window in tkinter goes under the toplevel tkinter window where topmost enabled-CodePudding

I will try to simplify my question here. My problem is like, on my first window of tkinter I have a button that opens another tkinter window. You can say it a second window to keep it on top I use win2.attributes('-topmost', True). Then I have a browse button to import file from the computer but when I click it goes under the window 2.

Following is my code.

from tkinter import *
from tkinter.filedialog import askopenfilename

root = Tk()
root.title("Base Window")
root.geometry("300x300")


def browse():
    file_to_open = askopenfilename()

def new_window():
    win2 = Toplevel(root)
    win2.title("Window 2")
    win2.geometry("300x300")
    win2.attributes('-topmost', True)
    Button2 = Button(win2, text="Browse", command=browse).pack()


button1 = Button(root, text="New window", command=new_window).pack()
root.mainloop()

My browse window is going under the window 2. Can you please suggest me the best way to keep it on top. I am sharing the screenshot of the problem as well

Starting code

Click on new window

Click browse button and the browse window is hidden

Cheers

CodePudding user response：

You need to set the parent option of askopenfilename() to the toplevel window win2:

from tkinter import *
from tkinter.filedialog import askopenfilename

root = Tk()
root.title("Base Window")
root.geometry("300x300")

def browse(parent):
    file_to_open = askopenfilename(parent=parent)

def new_window():
    win2 = Toplevel(root)
    win2.title("Window 2")
    win2.geometry("300x300")
    win2.attributes('-topmost', True)
    # pass 'win2' to browse()
    Button2 = Button(win2, text="Browse", command=lambda:browse(win2)).pack()


button1 = Button(root, text="New window", command=new_window).pack()
root.mainloop()