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Query to do indepth search for a regex is not working properly

Time:07-09

I'm having one query to do indepth search for a regex in mongoDB. I'm using JS function inside the query like this -

db.collection.find(
        {$where: function() {
        function  deepIterate(obj, value) {
        var new_value = new RegExp("^" value, "i");
        for (var field in obj) {
            if (obj[field] == new_value){
                return true;
            }
            var found = false;
            if ( typeof obj[field] === 'object' ) {
                found = deepIterate(obj[field], new_value)
                if (found) { return true; }
            }
        }
        return false;
    };
    return deepIterate(this, "[A-Ba-b0-9]*60.51[A-Ba-b0-9]*")
}}
)

It doesn't return any values, output is Fetched 0 record(s) in 4ms. But I'm having one string in my database - 192.108.60.51. That record is not getting returned. Help!!!

CodePudding user response:

You can change your regex pattern into deepIterate(this, "(([1-9]?\\d|1\\d\\d|2[0-5][0-5]|2[0-4]\\d)\\.){3}([1-9]?\\d|1\\d\\d|2[0-5][0-5]|2[0-4]\\d)$") this regex is for find string that is an Ip-Address. You can't find any record because your regex pattern not match with your record in database

CodePudding user response:

Found out the solution -

db.collection.find({$where: function() {
        function  deepIterate(obj, value) {
        new_value = new RegExp(value, 'i');
        for (var field in obj) {
            if (new_value.test(obj[field])){
                return true;
            }
            var found = false;
            if ( typeof obj[field] === 'object' ) {
                found = deepIterate(obj[field], new_value)
                if (found) { return true; }
            }
        }
        return false;
    };
    return deepIterate(this, "[A-Ba-b0-9]*60.51[A-Ba-b0-9]*")
}})
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