How to access a key within a nested dictionary(in a list that has dictionary)-CodePudding

I am very new to coding and I am trying to access a key(such as 'name') that is within a nested dictionary that has a list which holds all of the Dictionaries.

Ex. I want to access the Sex of the dictionary of people.

This is the code:

people = {1: [{"name": 'John'}, {'Age': '27'}, {'Sex': 'Male'}],
          2: [{"name": 'Marie'}, {'Age': '22'}, {'Sex': 'Female'}],
              }

for i, x in people.items():
    Accessing_People_List = people[i]
    print(people[i])
    print(type(people[i]))
    print(Accessing_People_List[i])

So far I could only access till the list part, after that everything went as well as a cook trying to do surgery on a live person.(no offense)

So could yall give me some or any suggestions on accessing it and explain how that code to does that? (cause this is some sort of a practice for myself ) GLHF.

TL;DR: need help to access a key of a nested dictionary with a list that holds several dictionaries Edit: Btw, thanks for asking

CodePudding user response：

The reason why you are having such problems is because your object structure makes no sense. Your inner lists contains 3 separate dictionaries with single key each. Drop the lists, make them 1 dictionary. -

1: {"name": 'John', 'Age': '27', 'Sex': 'Male'}

Now you can access it like this: people[1]["Sex"]. Or even better make name the key:

people = {"John": {'Age': '27', 'Sex': 'Male'},
          "Marie": {'Age': '22', 'Sex': 'Female'},
              }

print(people["John"]["Sex"])

Should you want to get it from your structure, you'd have to do something like this:

people[1][2]['Sex']

2 shows up because it dictionary that contains this info is index 2 element of the list.

CodePudding user response：

There's multiple ways to achieve this. I'm sure this question has already been answered in this thread: Safe method to get value of nested dictionary

One way is to chain gets, another is to use reduce and put this in a deep_get function so you can do this in a generic way. All of this you can find in the above link! Good luck!

CodePudding user response：

Assuming your dict is given and that you cannot change it by hand, you could do something like this to get the desired structure and then access each key:

from collections import ChainMap

people = {1: [{"name": 'John'}, {'Age': '27'}, {'Sex': 'Male'}],
          2: [{"name": 'Marie'}, {'Age': '22'}, {'Sex': 'Female'}],
              }

new_dict = {key: dict(ChainMap(*people[key])) for key in people}

new_dict[1]["Sex"] # -> 'Male'

If you do not want to import ChainMap, you can also use the following:

people = {1: [{"name": 'John'}, {'Age': '27'}, {'Sex': 'Male'}],
          2: [{"name": 'Marie'}, {'Age': '22'}, {'Sex': 'Female'}],
              }

new_dict = {key: {k:v for d in people[key] for k, v in d.items()} for key in people}

new_dict[1]["Sex"] # -> 'Male'