how can you sort by word count? sorted() sort me only by the number of numbers? Thank you for your help

def make_dict(s):
    w_dict = {}
    word_list = s.split()
    for wrd in word_list:
        w_dict[wrd] = w_dict.get(wrd,0)  1
    return w_dict

print(make_dict("test is test"))

input is print(make_dict("test is test tests tests tests")) output is {'test': 2, 'is': 1, 'tests': 3}

im search output tests ,test ,is

CodePudding user response：

You can change your code like approach_1 or use collections.Counter like approach_2.

1. You can sorted on dict.items() and return result as dict
2. Use Counter and return most_common.

Approach_1

def make_dict(s):
    w_dict = {}
    word_list = s.split()
    for wrd in word_list:
        w_dict[wrd] = w_dict.get(wrd,0)  1
    return dict(sorted(w_dict.items(), key=lambda x: x[1], reverse=True))

print(make_dict("test is test tests tests tests"))
# {'tests': 3, 'test': 2, 'is': 1}

Approach_2

from collections import Counter
def make_dict_2(s):
    word_list = s.split()
    c = Counter(word_list)
    return dict(c.most_common())

print(make_dict_2("test is test tests tests tests"))
#{'tests': 3, 'test': 2, 'is': 1}