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For loops to make leave-one-out analysis with netmeta

Time:07-21

I'm doing a network metanalysis of 29 studies using the "netmeta" package with R and I now have to do the leave-one-out analysis. I was thus wondering wether there is a way to use for loops to gain the results of such method in order not to do it by manually excluding one trial at the time.

I came up with this:

 for (i in 1:29){
  NMA_DB_L<-NMA_DB[-i,]
  yi_All_cause<-summary(escalc(ai= NMA_DB_L$All_Cause_d_C, bi=NMA_DB_L$PTS_All_Cause_d_C - NMA_DB_L$All_Cause_d_C,
                               ci= NMA_DB_L$All_Cause_d_I, di= NMA_DB_L$PTS_All_Cause_d_I - NMA_DB_L$All_Cause_d_I, 
                               measure = "RR"))[,"yi"]
  
 sei_All_cause<-summary(escalc(ai= NMA_DB_L$All_Cause_d_C, bi=NMA_DB_L$PTS_All_Cause_d_C - NMA_DB_L$All_Cause_d_C,
                               ci= NMA_DB_L$All_Cause_d_I, di= NMA_DB_L$PTS_All_Cause_d_I - NMA_DB_L$All_Cause_d_I, 
                               measure = "RR"))[,"sei"]
  
  netmeta(TE=yi_All_cause, seTE =  sei_All_cause, treat1 = NMA_DB_L$Arm_1, treat2 = NMA_DB_L$INT, sm="RR",
          studlab = NMA_DB_L$Study, reference.group = "Standard_DAPT")
}

and it seems to work properly, but I cannot find a way to save the results of each analysis without one of the trials.

Does anyone have an idea of how to do so?

Thanks in advice.

CodePudding user response:

Why not save the outputs of netmeta function into a list?

# Create list of length 29
net_results <- vector('list', 29)

for (i in 1:29) {
    NMA_DB_L<-NMA_DB[-i,]

    ...

    net <- netmeta(TE=yi_All_cause, seTE =  sei_All_cause,
            treat1 = NMA_DB_L$Arm_1, treat2 = NMA_DB_L$INT, sm="RR",
            studlab = NMA_DB_L$Study, reference.group = "Standard_DAPT")
    net_results[[i]] <- net
}

You can then access results of the specific run with net_results[[1]] etc.

R lists can in general contain any type of element which makes it a suitable structure for this type of problems.

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