I have a data having table name users
that has fields of id, role_id, first_name, last_name, name, and email
. What I trying to get is the role_id of 2 with any match from the name, first_name, or last_name.
Laravel Framework 8.77.1
PHP 7.4.3
What I am trying is the Laravel Query
public function search_friend_custom(Request $request) {
$search = $request->input('search');
$search = 'chase ';
// ** $Search variable has chase string for searching.**
$friends = DB::table('users')
->select('users.*','users.id as user_tab_id')
->where('role_id', 2)
->where('name', 'like', '%' . $search . '%')
->orWhere('first_name', 'like', '%' . $search . '%')
->orWhere('last_name', 'like', '%' . $search . '%')
->paginate(10);
return view('user.custom_search' , compact('friends'));
}
What it is returing are both Chase's Hadyman Services with role_id=3 and Chase Mary role_id=2 both. But the aspected result is only Chase Mary as it's role_id is 2
.
Please guide, I am not getting what I am missing here?
CodePudding user response:
You should logically group them inside a closure so your role_id
takes precedence but doesn't interfere with the rest of the query.
$friends = DB::table('users')
->select('users.*','users.id as user_tab_id')
->where('role_id', 2)
->where(fn($builder) => $builder->where('name', 'like', '%' . $search . '%')
->orWhere('first_name', 'like', '%' . $search . '%')
->orWhere('last_name', 'like', '%' . $search . '%')
)->paginate(10);
See the documentation for more references.