Create a function that call methods in a class in typescript-CodePudding

normally class method call like

classA.method1(args)

But I want to make it a function which takes methodName and arguments to pass in and return the method result.

const function = (methodName, args = []) => {
  return classA[methodName](...args);
}

there are errors in the above code.

At the end I want to do something like:

function(methodName, [args])

to call classA's methodName method and return the result

How to write it in typescript? Thanks

CodePudding user response：

Maybe this can help you start in the right way. The example below is not very typesafe since there is some casting to any

class classA {
  static methodA1() {
    console.log('A1')
  }

  static methodA2(arg: string) {
    console.log(`A2: ${arg}`)
  }
}

const executeFunc = (funcName: string, args: any[] = []) => {
  return (classA as any)[funcName](...args)
}

executeFunc('methodA1')
executeFunc('methodA2', ['input argument!'])

I have a classA class with two methods that I can call in executeFunc