Project_id | Employee_id |
---|---|
1 | 1 |
1 | 2 |
2 | 1 |
Write a sql query that reports all the projects that have the most employee
Project_id |
---|
1 |
select temp.project_id from
(select project_id, count(distinct employee_id)
from Project
group by project_id
order by count(distinct employee_id) desc
)temp
limit 1
select project_id from Project
group by project_id
having count(project_id)=
(select count(project_id) from Project
group by Project_id
order by count(project_id) desc
limit 1)
CodePudding user response:
Assuming employee_ids are unique per project, both would work. Otherwise first would work.
EDIT: This DBFiddle demo explains why first one would always work while second wouldn't if employee_ids are not unique per project.