Best way to filter an array by multiple properties?-CodePudding

I'm trying to filter an array and remove the entries that contain certain properties. For example, my array looks like this:

const items = [{a: "apple", b: "banana", c: "coconut"}, {a: "apple"}, {b: "banana, c: "coconut"}];

And I want to filter out the items that have the properties b or c.

Right now I have:

items.filter(item => "b" in item || "c" in item);

but I feel like there is a better way to do this, and set it up so a lot more properties could easily be added in the future.

CodePudding user response：

Put the property names in an array, and use .some() to test if any of those properties exists.

const items = [{
  a: "apple",
  b: "banana",
  c: "coconut"
}, {
  a: "apple"
}, {
  b: "banana",
  c: "coconut"
}];

let properties_to_filter = ["b", "c"]
let result = items.filter(item => properties_to_filter.some(prop => prop in item));

console.log(result);

CodePudding user response：

      const items = [{a: "apple", b: "banana", c: "coconut"}, {a: "apple"}, {b: "banana", c: "coconut"}]

      let filtredKey = ["a"]

      let result = []
      items.map(el => {
        if(el.hasOwnProperty("c"))
          result.push(el)
      })

      console.log(result)