regeexp matching words from the back pattern-CodePudding

I have problem with regex /!!(\w*)!!(?!\w)/g is matching me backwards because I needed check it from end to beggining. I will explain on examples whats wrong:

examples:

!!foo!!bar!! - should match only bar, works correct

!!foo!!!!bar!! - should match foo and bar, works correct

!!foo!!!!bar!!test - should match foo and bar, works not correct now only matching foo

CodePudding user response：

you could create a reverseString function like

function reverseString(str) {
    return str.split("").reverse().join("");
}

now if you apply reverseString on your input (and the matcher result) you can go along with the simple RegExp !!\w !!

CodePudding user response：

Use Regex: /!!(\w*)!!/g

var st = ['!!foo!!bar!!', '!!foo!!!!bar!!', '!!foo!!!!bar!!test'];

st[0].split("").reverse().join("").match(/!!(\w*)!!/g).map(x => x.split("").reverse().join("").replace(/!/g, '')).reverse()  // ['bar']
st[1].split("").reverse().join("").match(/!!(\w*)!!/g).map(x => x.split("").reverse().join("").replace(/!/g, '')).reverse()  // ['foo', 'bar']
st[2].split("").reverse().join("").match(/!!(\w*)!!/g).map(x => x.split("").reverse().join("").replace(/!/g, '')).reverse() // ['foo', 'bar']

   or

st.map(y => y.split("").reverse().join("").match(/!!(\w*)!!/g).map(x => x.split("").reverse().join("").replace(/!/g, ''))).map(z => z.reverse())
// [['bar'], ['foo', 'bar'], ['foo', 'bar']]