I have a form in my react application which is inside a modal pop up. so when the user closes the pop up i want to check if there is any changes made in the form fields.If so i will show a confirmation modal and if no changes i will close the pop up.
<FormProvider {...methods}>
<form onSubmit={handleSubmit(submitDetails)}>
<FormInput
onChange={handleChange(onChange, value)}
onBlur={onBlur}
value={value ?? ""}
name="name"
/>
<FormInput
onChange={handleChange(onChange, value)}
onBlur={onBlur}
value={value ?? ""}
name="age"
/>
<section className="submit-section">
<Button onClick={() => checkUnsavedAndClose()}>Cancel</Button>
<Button type="submit" disabled={!isValid}>
Save
</Button>
</section>
</form>
</FormProvider>
const checkUnsavedAndClose = () => {
// if the form is not updated
closePopUp();
// if the form is updated
alertPopup();
}
What is the best approach to validate the entire form irrespective of number of fields in it. i was thinking of checking whether the form is touched or dirty. but i am not sure that it would be the best solution. any inputs will be highly appreciated
CodePudding user response:
Assuming the "handleChange" function is used for all inputs one thing you could do is use it to hold on state a variable for changes
handleChange(onChange, value) {
value !== originalValue && setState({anyChanges: true}) //or useState and set the state inside the modal
onChange(value)
}
you could also hold which fields were modified and not save to improve the pop-up message
CodePudding user response:
by creating a boolean changed
state. that you can change true/false. And you check the value when you try to close the popup.
const [changed, setChanged] = useState(false);
const handleChange() {
// your code
setChanged(true)
}
const checkUnsavedAndClose = () => {
if(changed) {
alertPopup();
} else {
closePopUp();
setChanged(false)
}