How to compare two objects but skip values and just compare keys and key types?-CodePudding

I want to write unit testing using Jest for my Node.js functions and need to test if response object has some specific keys or not. Something like this:

expect(await mokChannelsService.getChannel(inputDto)).toEqualKeys(outputDto);

// Or just a normal function

const result = await mokChannelsService.getChannel(inputDto);
const equal = isEqualKeys(result, outputDto);

This toEqualKeys function should check equality just for keys not values. And these objects are not instances of a class. for example these two objects should be equal:

const object1 = {
  names: {
    firstName: '',
    lastName: '',
  },
  phone: 1,
};

const object2 = {
  names: {
    firstName: 'John',
    lastName: 'Due',
  },
  phone: 1234567890,
};

const object3 = {
  names: {
    firstName: 'John',
    lastName: 12,
  },
  mobile: '12345',
};

const result1 = toEqualKeys(object1, object2); // true
const result1 = toEqualKeys(object1, object3); // false

Is there any NPM packages available for this?

CodePudding user response：

You can iterate each of the keys in object1, checking that the same key exists in object2 and - if the associated property in object1 is an object, that all the keys from that object also exist in a similar object in object2:

const object1 = {
  names: {
    firstName: '',
    lastName: '',
  },
  phone: 1,
};

const object2 = {
  names: {
    firstName: 'John',
    lastName: 'Due',
  },
  phone: 1234567890,
};

const object3 = {
  names: {
    firstName: 'John',
    lastName: 12,
  },
  mobile: '12345',
};

const toEqualKeys = (obj1, obj2) => Object.keys(obj1)
  .every(k => k in obj2 && 
    (typeof obj1[k] != 'object' || typeof obj2[k] == 'object' && toEqualKeys(obj1[k], obj2[k]))
  )
  
console.log(toEqualKeys(object1, object2))
console.log(toEqualKeys(object1, object3))