I am trying to automate a curl
command in a VS Code task.
The full curl command without headers and auth should look something like:
curl -X PUT http://localhost:9000/schema/schemaName -d @schemaName-schema.json
Currently my task command looks like this:
curl -X PUT http://localhost:9000/schema/${fileBasename} -d @${fileBasename}
And fileBasename would be schemaName-schema.json
I want to split the fileBasename on the dash -
, is this possible inside the VS Code command syntax?
CodePudding user response:
You can try if the snippet variable find replace also works for task variables
${fileBasename/^(. ?)-.*$/$1/}
Or you can use the extension Command Variable
{
"version": "2.0.0",
"tasks": [
{
"label": "echo some var",
"type": "shell",
"command": "curl -X PUT http://localhost:9000/schema/${input:fileBasenamePart} -d @${fileBasename}",
"problemMatcher": []
}
],
"inputs": [
{
"id": "fileBasenamePart",
"type": "command",
"command": "extension.commandvariable.transform",
"args": {
"text": "${fileBasename}",
"find": "^(. ?)-.*$",
"replace": "$1"
}
}
]
}