Find similar items from an array filtered by the provided data-CodePudding

trying to solve the problem here. so I have an array of objects and the object contains some properties and their values. so I want to find the objects that have similar values filtered by the props that I'm providing.

here's the code that I've done but the issue is I need to have all the object's properties have the same values as each other.

const data = [
    {
        id: 1,
        name: 'ali',
        class: 12,
        thisSec: true
    },
    {
        id: 2,
        name: 'vicks',
        class: 11,
        thisSec: false
    },
    {
        id: 3,
        name: 'ali',
        class: 12,
        thisSec: true
    },
    {
        id: 4,
        name: 'vicks',
        class: 11,
        thisSec: false
    },
    {
        id: 5,
        name: 'nick',
        class: 10,
        thisSec: true
    },
    {
        id: 6,
        name: 'lick',
        class: 12,
        thisSec: false
    },
]

const checkFilter = (id, searchCritera) => {
    if(id && searchCritera.length) {
        const selectedItem = data.find(item => item.id === id)
        
        const dataneeded = []
        searchCritera.forEach((item) => {
            data.forEach(dataItem => {
                if(dataItem.id !== selectedItem.id) {
                    if(dataItem[item] === selectedItem[item]) {
                        const ifElemExists = dataneeded.find(dataNeddedItem => dataNeddedItem.id == dataItem.id)
                        if(!ifElemExists) {
                            dataneeded.push(dataItem)   
                        }
                    }
                }
            })
        })
        
        console.log('dataneeded ', dataneeded);
    }
}

checkFilter(1, [
    'name',
    'class'
])

output:

I am filtering with name and class props but the output I'm getting is having the name as different values.

any help would be really appreciated. thanks.

CodePudding user response：

Try this filter

const checkFilter = (id, searchCritera) => {
    if(id && searchCritera.length) {
        var keyToIgnore = ["id"];
        const selectedItem = data.find(item => item.id === id)
        const targetWithoutSelectedItem = data.filter(item => item !== selectedItem);
        const targets = targetWithoutSelectedItem.filter(item => {
          return Object.keys(item).every(obj => keyToIgnore.includes(obj) || item[obj] === selectedItem[obj] );
        })

        console.log('dataneeded ', targets);
    }
}

CodePudding user response：

You can use the Array#filter method to filter based on selectedItem properties supplied. To exclude selectedItem use o.id !== id as in the demo below:

const data = [ { id: 1, name: 'ali', class: 12, thisSec: true }, { id: 2, name: 'vicks', class: 11, thisSec: false }, { id: 3, name: 'ali', class: 12, thisSec: true }, { id: 4, name: 'vicks', class: 11, thisSec: false }, { id: 5, name: 'nick', class: 10, thisSec: true }, { id: 6, name: 'lick', class: 12, thisSec: false }, ],

checkFilter = (id, searchCritera) => {
    if(id && searchCritera.length) {
        const selectedItem = data.find(item => item.id === id);
        const dataneeded = data.filter(
            o => o.id !== id && o.name === selectedItem.name && o.class === selectedItem.class
        );       
        console.log('dataneeded ', dataneeded);
    }
};

checkFilter(1, [
    'name',
    'class'
]);