I am writing a function that is supposed to count duplicates and mention how many duplicates are of each individual record. For now my output is giving me the total number of duplications, which I don't want.

i.e. if there are 4 duplicates of one record, it's giving me 4 instead of 1; if there are 6 duplicates of 2 individual records it should give me 2.

Could someone please help find the bug?

Thank you

def duplicate_count(text):
text = text.lower()
dict = {}
word = 0
if len(text) != "":
    for a in text:
        dict[a] = dict.get(a,0)   1
    for a in text:
        if dict[a] > 1:                
            word = word   1
    return word
else:
    return "0"
        
            
            

CodePudding user response：

Fixed it:

def duplicate_count(text):
text = text.lower()
dict = {}
word = 0
if len(text) != "":
    for a in text:
        dict[a] = dict.get(a,0)   1
    return sum(1 for a in dict.values() if a >= 2) 
else:
    return "0"
        

CodePudding user response：

You can do this with set and sum. First set is used to remove all duplicates. This is so we can have as few iterations as possible, as-well-as get an immediate count, as opposed to a "one-at-a-time" count. The set is then used to create a dictionary that stores the amount of times a character repeats. Those values are then used as a generator in sum to sum all the times that the "repeat value" is greater than 1.

def dup_cnt(t:str) -> int:
    if not t: return 0

    t = t.lower()
    d = dict()
    
    for c in set(t): 
        d[c] = t.count(c)

    return sum(v>1 for v in d.values())

print(dup_cnt('aabccdeefggh')) #4