calculaNumeroDaSenha(['0110100000', '1001011111','1110001010', '0111010101','0011100110', '1010011001', '1101100100', '1011010100', '1001100111', '1000011000']);

function calculaNumeroDaSenha(senha) {

    for (let i = 0; i < senha.length; i  ) {
     var dividir = senha[i].split('');

     function filtro1(modo1) {
      return modo1 == "1"
    }
    function filtro2(modo2) {
      return modo2 == "0"
    }
    etapaFinal(dividir.filter(filtro1), dividir.filter(filtro2));
    function etapaFinal(x,y) {
      var novaArray = [];
      if (x.length > y.length || x.length == y.length) {
        novaArray.push('1')}
      else {
        novaArray.push('0');
       }
       console.log(novaArray);

      };
 
    } 
  }

the code output looks like this:

 ['0']
 ['1']
 ['1']
 ['1']
 ['1']
 ['1']
 ['1']
 ['1']
 ['1']
 ['0']

But I want the output to come out in just an array, like this:

['0111111110']

I've already tried methods like the join() function, but it didn't work:

    function etapaFinal(x,y) {
      var novaArray = [];
      if (x.length > y.length || x.length == y.length) {
        novaArray.push('1')}
      else {
        novaArray.push('0');
       }
       for (let a = 0; a < novaArray.length; a  ) {
        console.log(novaArray[i].join());
       }
      
      };

Please, if you have any idea how to do this, no matter how, help me if possible.

CodePudding user response：

So it seems like your fundamental misunderstanding is how .push works. Push, as the name implies, pushes a new value to the end of the array. Thus instead of pushing to an array, what you need to do is just build up a string and then push that string at the end.

Looks like your code will either return a 1 or a 0 depending on what filter. Thus your new code can look like so:

function calculaNumeroDaSenha(senha) {
      let result = '';
    for (let i = 0; i < senha.length; i  ) {
       var dividir = senha[i].split('');

       const filtro1 = (modo1) => {
        return modo1 == "1"
      }

      const filtro2 = (modo2) => {
        return modo2 == "0"
      }

      const etapaFinal = (x,y) => {
        if (x.length > y.length || x.length == y.length) {
          return '1';
        }
        else {
          return '0';
        }
      };
 
            result  = etapaFinal(dividir.filter(filtro1), dividir.filter(filtro2));     
    } 
    
    return [result];
  }

Where if we then log it out as so: console.log(calculaNumeroDaSenha(['0110100000', '1001011111','1110001010', '0111010101','0011100110', '1010011001', '1101100100', '1011010100', '1001100111', '1000011000']));

we get an array of size 1 of the following results: ['0111111110']. JSFiddle: https://jsfiddle.net/avnkj81z/

One thing I did, is I changed your inner function blocks to be defined instead using the following pattern: const <functionName> = <(parameters)> => {...}. This is because it makes it easier to read and you don't have one function nested in one after the other. Note that function A(b) { returns b; } is equivalent to const A = (b) => { returns b;}

CodePudding user response：

To join all the strings into one string, use Array.join().

CodePudding user response：

The question is kinda vague, you need to clarify what you're looking for:

if you are looking to group an array items into one string, you would use Array.join().

const arr = ['0110100000', '1001011111','1110001010', '0111010101','0011100110', '1010011001', '1101100100', '1011010100', '1001100111', '1000011000']
arr.join(''); 
// the above command would result in a single string with all array values concatenated
// "0110100000100101111111100010100111010101001110011010100110011101100100101101010010011001111000011000"

However if you're looking to group all array elements into one array that has a single string with all array elements grouped, you would use Array.join() followed by String.split()

const arr = ['0110100000', '1001011111','1110001010', '0111010101','0011100110', '1010011001', '1101100100', '1011010100', '1001100111', '1000011000']
arr.join('').split(); 
// the above command would result in a single array with one string with all array elements grouped
// [ "0110100000100101111111100010100111010101001110011010100110011101100100101101010010011001111000011000" ]

CodePudding user response：

I think you want the output of this code. Please look into it. It is printing your desired value.

calculaNumeroDaSenha(['0110100000', '1001011111', '1110001010', '0111010101', '0011100110', '1010011001', '1101100100', '1011010100', '1001100111', '1000011000']);

function calculaNumeroDaSenha(senha) {

  var novaArray = [];
  var str = '';
  for (let i = 0; i < senha.length; i  ) {
    var dividir = senha[i].split('');

    function filtro1(modo1) {
      return modo1 == "1"
    }
    function filtro2(modo2) {
      return modo2 == "0"
    }
    etapaFinal(dividir.filter(filtro1), dividir.filter(filtro2));
    function etapaFinal(x, y) {
      if (x.length > y.length || x.length == y.length) {
        str  = 1;
      }
      else {
        str  = 0;
      }


    };

  }
  novaArray.push(str);
  console.log(novaArray);
}