How I am to pass specific xml fragment, which the i save in variable, in <xsl:call-template>?-CodePudding

I need save node and pass this node in <xsl:call-template name="update.target">, how i can do this ? I searched for information on the Internet, I could not find

XML

<?xml version="1.0" encoding="UTF-8"?>
<catalog>
  <cd>
    <title>Empire Burlesque</title>
    <artist>Bob Dylan</artist>
    <country>USA</country>
    <company>Columbia</company>
    <price>10.90</price>
    <year lol="1">1985</year>
  </cd>
<cd>
    <title>Empire Burlesque</title>
    <artist>Bob Dylan</artist>
    <country>USA</country>
    <company>Columbia</company>
    <price>10.90</price>
    <target>
      <first>Jane</first>
      <second>Lane</second>
    </target>
  </cd>
</catalog>

XSLT


<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html> 
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>

<xsl:template match="catalog">
  <xsl:if test="cd/target">
    <xsl:call-template name="update.target">
     <!-- pass <target> node in update.target template -- >
    </xsl:call-template>
  </xsl:if>
</xsl:template>

<xsl:template name="update.target">
 ... do something
</xsl:template>
</xsl:stylesheet>

I try use xsl:param and xsl:with-param, but I could not.

CodePudding user response：

There are different changes to be considered.

Introduce param to the template output.target:

<xsl:template name="update.target">
    <xsl:param name="target" />

Pass some target to updated.target:


        <xsl:if test="cd/target">
            <xsl:call-template name="update.target">
                <xsl:with-param name="target" select="cd/target"/>

To output the passed param, you can use value-of:


        <xsl:value-of select="$target/first/text()" />