How can I randomize a number with 32 hexadecimal digits?-CodePudding

I am trying to randomize a number with 32 hexadecimal digits in bash with seed which depends on the date.
I thought about something like: RANDOM=$(date %N | cut -b4-9) , but it's not give me 32 hexadecimal digits.

ideas?

CodePudding user response：

I'm always generating with: openssl rand -base64 32

CodePudding user response：

Feed /dev/urandom to tr and delete all but hex digits:

$ tr -dc '[:xdigit:]' < /dev/urandom | head -c32
90D75De9CaA0C38a15B8facf59CBBDdc

If you need all upper (or all lower):

$ tr -dc '0-9A-F' < /dev/urandom | head -c32
CBABC737B0F9C059531CA7672FCA52F6

$ tr -dc '0-9a-f' < /dev/urandom | head -c32
87fa3f2e4f98a8e8eecb8236e2736eba

CodePudding user response：

Eliminate your need for the date.
If it's an assignment, say so.

Assuming it is -

$: src="0123456789ABCDEF" && RANDOM=$(( $(date  %s) % 32767 ))    &&
>  for c in {1..32}; do printf "%s" ${src:$((RANDOM)):1}; done &&
>  echo 
14E4552562D03BB6FCAC8602B0D38BE7