How to match the string after the character and space in Python3?-CodePudding

I have the following string:

'- Submission GMV / return finance027110/06 Abdul Rahman -26,00- Submission GMV / return finance02432548/08 Michael Scott -56,47- GMV success. 452630/10/21 Lehazq998890/92 60,00'

How can I return the values as:

[['- Submission PVT / return finance027110/06 Abdul Rahman','-26,00'],
 ['- Submission LTD / return finance02432548/08 Michael Scott','-56,47'],
 ['- GMV success. 452630/10/21 Lehazq998890/92', ' 60,00']]

I'm looping into multiple input. Hence, the count of output rows differs in each iteration. But the split pattern remains same.

CodePudding user response：

Your requirement is easy to come by using re.findall with two capture groups:

inp = "- Submission GMV / return finance027110/06 Abdul Rahman -26,00- Submission GMV / return finance02432548/08 Michael Scott -56,47- GMV success. 452630/10/21 Lehazq998890/92  60,00"
matches = re.findall(r'(-.*?) ([ -]\d (?:,\d )?)', inp)
print(matches)

This prints:

[('- Submission GMV / return finance027110/06 Abdul Rahman', '-26,00'),
 ('- Submission GMV / return finance02432548/08 Michael Scott', '-56,47'),
 ('- GMV success. 452630/10/21 Lehazq998890/92', ' 60,00')]

CodePudding user response：

try something like this data.split('- ')[1:]