How to send a variable from Laravel Controller to a Python script?-CodePudding

$client = new Client();
$a = 'https://scholar.google.com/citations?user=';
$gscID = 'EnegzCwAAAAJ';//for eg
$b = '&hl=en&oi=ao';
$url = $a . $gscID . $b;

$crawler = $client->request('GET', $url);

//python script
$process = new Process(['python', public_path() . '\ext.py'], null, ['SYSTEMROOT' => getenv('SYSTEMROOT'), 'PATH' => getenv("PATH")]);
$process->run();

// executes after the command finishes
if (!$process->isSuccessful()) {
    throw new ProcessFailedException($process);
}
$out[] = $process->getOutput();
dd($out);

Extracting the tables from the given url webpage

Now I want to pass the $url variable to the python script stored in my public folder because everytime my url changes with different person's ID.

Any help would be really appreciated

CodePudding user response：

You can add script parameters in the array that you are passing to Process. Here is the doc.https://symfony.com/doc/current/components/process.html#using-features-from-the-os-shell

CodePudding user response：

Found out an easy solution $output = shell_exec("python ext.py $url");//ext.py is name of my script and $url is my variable which I want to pass

And then in python script write

import sys
url = sys.argv[1]