Regex specific number inside quote-CodePudding

I am new to regex and have this cdn url that returns text and I want to use javascript to match and extract the version number. I can match the latestVersion but I am not sure how to get the value inside of it.

ex on text:

...oldVersion:"1.2.0",stagingVersion:"1.2.1",latestVersion:"1.3.0",authVersion:"2.2.2"...

I tried doing this line to display latestVersion:"1.3.0 but not successful

const regex = /\blatestVersion:"*"\b/
stringIneed = text.match(regex)

And I only need 1.3.0 not including the string latestVersion:

CodePudding user response：

You could use a lookbehind, or a capturing group like this:

const str = '...oldVersion:"1.2.0",stagingVersion:"1.2.1",latestVersion:"1.3.0",authVersion:"2.2.2"...'

console.log(
  str.match(/(?<=latestVersion:")[^"] /)?.[0]
)

console.log(
  str.match(/latestVersion:"([^"] )"/)?.[1]
)

CodePudding user response：

Try adding a capture group () to match certain strings in the Regex.

/\blatestVersion:"([0-9.] )"/

CodePudding user response：

There are many ways of doing it. This is one:

const text='...oldVersion:"1.2.0",stagingVersion:"1.2.1",latestVersion:"1.3.0",authVersion:"2.2.2"...';

console.log(text.match(/latestVersion:"(.*?)"/)?.[1])

The .*? is a "non-greedy" wildcard that will match as few as possible characters in order to make the whole regexp match. For this reason it will stop matching before the ".