I have a grammar that at some point has the following rule:
boolConst :
'true'
| 'false';
This leads to the following code (with visitor activated) being generated:
class BoolConstContext : public antlr4::ParserRuleContext {
public:
BoolConstContext(antlr4::ParserRuleContext *parent, size_t invokingState);
virtual size_t getRuleIndex() const override;
antlr4::tree::TerminalNode *TRUE();
antlr4::tree::TerminalNode *FALSE();
virtual std::any accept(antlr4::tree::ParseTreeVisitor *visitor) override;
};
If I understand this correctly I cannot use the visitor to decent into the tree further, or at least I cannot find a visitTRUE
or visitFALSE
function in the BaseVisitor
class.
Now when implementing a visitor based on the BaseVisitor
I have to implement the function virtual std::any visitBoolConst(BoolConstContext *ctx) override
.
However, I now need to know which of the two were parsed, whether it was FALSE, or TRUE So I am wondering if doing something like the following is correct and what should be done.
if (ctx->FALSE() != nullptr) {
// false was parsed
} else if (ctx->TRUE() != nullptr) {
// true was parsed
} else {
throw std::exception();
}
CodePudding user response:
If you were to use named alternatives:
boolConst :
'true' # boolConstTrue
| 'false' # boolConstFalse;
ANTLR will generate different Context classes for each alternative (BoolConstTrueContext
and BoolConstFalseContext
). Then the value would be implicit in the type.