How to remove last 3 numbers from this line? Flutter-CodePudding

Hello there i have this Datacells and i want to remove the last 3 numbers, here is my code line :

DataCell(Text((DateTime.parse(e['start'].toString()).toLocal().toString()))),

CodePudding user response：

Try the following code:

DataCell(Text((DateTime.parse(e['start'].toString()).toLocal().toString()).replaceAll(".333", ""))),

CodePudding user response：

You can take this as an example:

final text = "2022-06-12 16:34:45:333";
print(text.substring(0, text.length-4)); // 2022-06-12 16:34:45

This will remove the last 3 letters and ":" from it.

Another solution, you can also do this:

  final text = "2022-06-12 16:34:45:333";
  final asList = text.split(":");
  asList.removeLast();
  print(asList.join(":")); // 2022-06-12 16:34:45

CodePudding user response：

you can use the substring method on the string you get;
In particular, you can first calculate how the string should look like:

String dateString = DateTime.parse(e['start'].toString()).toLocal().toString();
String truncatedDateString = dateString.substring(0, dateString.length - 4);

and then use the truncatedDateString variable in your DataCell:

DataCell(Text(truncatedDateString));

CodePudding user response：

Simply take the first 20 characters

DateTime.parse(e['start'].toString()).toLocal().toString().substring(0,19); //2022-06-01 14:28:56

or as mmcdon20 said use the intl package

import 'package:intl/intl.dart';
...
DateTime now = DateTime.now();
  String formattedDate = DateFormat('yyyy-MM-dd – kk:mm:ss').format(now); //2022-12-19 – 10:32:05