Pass Bash array in cURL POST call in Shell script-CodePudding

I am trying to do a curl call in my shell script where i want to pass the result of sql in data.

Please assume I have result stored in array as liveCalculators

curl_response=`curl -k -X POST "https://myapiurl" -H "accept: */*" -H "Content-Type: application/json" -d "{ \"keys\": [], \"calcs\": ${liveCalculators[@]}}" -w ";%{http_code}"`

I get Bad Request as error

Please suggest what can be done to fix it.

CodePudding user response：

Your array output is not encapsulated as a valid JSON, so how about this:

curl_response=$(curl -k -X POST "https://myapiurl" -H "accept: */*" -H "Content-Type: application/json" -d "{ \"keys\": [], \"calcs\": \"${liveCalculators[@]}\" }" -w ";%{http_code}")

In addition, the output of the array liveCalculators is a BASH list, and you might need to do some parsing and search/replace, to convert it to a valid JSON list..

CodePudding user response：

If you have jq installed, try this :

curl_response="$(curl -k -X POST "https://myapiurl"\
    -H "accept: */*"\
    -H "Content-Type: application/json"\
    -w ";%{http_code}"\
    -d "$(jq -cn '{"keys": [], "calcs": $ARGS.positional}' --args "${liveCalculators[@]}")"
)"

CodePudding user response：

Like this :

myFlatArr=$(
    echo "${liveCalculators[@]}" |
         perl -lnE 'print join ", ", map { "\042$_\042" } split / /'
)
curl -k -X POST "https://myapiurl" \ 
    -H "accept: */*" \
    -H "Content-Type: application/json" \
    -w ";%{http_code}" \
    -d "@/dev/stdin" <<EOF
{ "keys": [], "calcs": [ $myFlatArr ] }
EOF