Slice Dataframe in sub-dataframes when specific string in column is found-CodePudding

Assume I have the dataframe df and I want to slice this in multiple dataframes and store each in a list (list_of_dfs).

Each sub-dataframe should only contain the rows "Result". One sub-dataframe starts, when in column "Point" the value "P1" and in column "X_Y" the value "X" is given.

I tried this with first finding the indicies of each "P1" and then slicing the overall dataframe within a list comprehension using the indicies of "P1". But I receive a list with two empty dataframes. Can someone advise? Thanks!

import pandas as pd

df = pd.DataFrame(
    {
        "Step": (
            "1", "1", "1", "1", "1", "2", "2", "2", "2", "2", "Result", "Result", "Result", "Result", "Result",
            "1", "1", "1", "1", "1", "2", "2", "2", "2", "2", "Result", "Result", "Result", "Result", "Result"
        ),
        "Point": (
            "P1", "P2", "P2", "P3", "P3", "P1", "P2", "P2", "P3", "P3", "P1", "P2", "P2", "P3", "P3",
            "P1", "P2", "P2", "P3", "P3", "P1", "P2", "P2", "P3", "P3", "P1", "P2", "P2", "P3", "P3",
        ),
        "X_Y": (
            "X", "X", "Y", "X", "Y",  "X", "X", "Y", "X", "Y", "X", "X", "Y", "X", "Y", 
            "X", "X", "Y", "X", "Y",  "X", "X", "Y", "X", "Y", "X", "X", "Y", "X", "Y",
        ),
        "Value A": (
            70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72,
            70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72, 
        ),
        "Value B": (
            70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72,
            70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72, 70, 68, 66.75, 68.08, 66.72,
        ),
    }
)

dff = df.loc[df["Step"] == "Result"]

value = "P1"
tuple_of_positions = list()

result = dff.isin([value])

seriesObj = result.any()
columnNames = list(seriesObj[seriesObj == True].index)

for col in columnNames:
    rows = list(result[col][result[col] == True].index)
    for row in rows:
        tuple_of_positions.append((row, col))

length_of_one_df = (len(dff["Point"].unique().tolist()) * 2 ) - 1

list_of_dfs = [dff.iloc[x : x   length_of_one_df] for x in rows]

print(list_of_dfs)

CodePudding user response：

sub    = df.query("Step == \"Result\"")
pivots = sub[["Point", "X_Y"]].eq(["P1", "X"]).all(axis=1)
out    = [fr for _, fr in sub.groupby(pivots.cumsum())]

get the subset of the frame where Step is equal to "Result"
check in which rows there is "P1" and "X" sequence
- that gives a True/False series
- cumulative sum of it determines the group as the "pivoting" (turning) points will be True since False == 0 in numeric context
- iterating over a GroupBy object yields "group_label, sub_frame" pairs, out of which we pull the sub_frames

to get

>>> out

[      Step Point X_Y  Value A  Value B
 10  Result    P1   X    70.00    70.00
 11  Result    P2   X    68.00    68.00
 12  Result    P2   Y    66.75    66.75
 13  Result    P3   X    68.08    68.08
 14  Result    P3   Y    66.72    66.72,
       Step Point X_Y  Value A  Value B
 25  Result    P1   X    70.00    70.00
 26  Result    P2   X    68.00    68.00
 27  Result    P2   Y    66.75    66.75
 28  Result    P3   X    68.08    68.08
 29  Result    P3   Y    66.72    66.72]

where the intermediares were

>>> sub

      Step Point X_Y  Value A  Value B
10  Result    P1   X    70.00    70.00
11  Result    P2   X    68.00    68.00
12  Result    P2   Y    66.75    66.75
13  Result    P3   X    68.08    68.08
14  Result    P3   Y    66.72    66.72
25  Result    P1   X    70.00    70.00
26  Result    P2   X    68.00    68.00
27  Result    P2   Y    66.75    66.75
28  Result    P3   X    68.08    68.08
29  Result    P3   Y    66.72    66.72

>>> pivots 

10     True
11    False
12    False
13    False
14    False
25     True
26    False
27    False
28    False
29    False
dtype: bool

# groups
>>> pivots.cumsum()

10    1
11    1
12    1
13    1
14    1
25    2
26    2
27    2
28    2
29    2
dtype: int32