I've successfully made a scraper that scrapes all 109 pages of the iPhone section on eBay.
The problem is that I need them to print on the same line. This is what it currently looks like
package main
import (
"fmt"
"github.com/gocolly/colly"
)
func main() {
c := colly.NewCollector(colly.UserAgent("Mozilla/5.0 (X11; Linux x86_64; rv:108.0) Gecko/20100101 Firefox/108.0"))
c.OnHTML(".s-item__title", func(element *colly.HTMLElement) {
element.ChildAttr("heading", "role")
fmt.Println(element.Text)
})
c.OnHTML(".s-item__price", func(element *colly.HTMLElement) {
fmt.Println(element.Text)
})
c.Visit("https://www.ebay.com/sch/i.html?_from=R40&_nkw=iPhone&_sacat=0&_pgn=1")
}
It's not even possible to navigate around this information. Can someone show me how I can get the Title along with the price on the same line?
I thought about renaming the element but it didn't work.
I would use printf or println, but then it just prints everything together.
CodePudding user response:
The fmt.Println()
includes '\n
' at the end. ln
means new line. You can use fmt.PrintF()
to format output however you want, it doesn't force a new line, if this is your issue.
CodePudding user response:
Try using fmt.Print instead of fmt.Println