As shown in figure, instruction is mov av, 0123 h,
1) why do 20000 position memory out B8?
2) why do you want to get B8 into instruction buffer?
3) since B8 also into the buffer, why the AX register only saved 0123 h?

CodePudding user response:

B8 is part of the instruction, operation code; So is necessarily exist, are to be of the instruction buffer; The role of the instruction is to deposit a number immediately to ax, ax is 0123,

CodePudding user response:

reference 1/f, zara's reply:

B8 is part of the instruction, operation code; So is necessarily exist, are to be of the instruction buffer; The role of the instruction is to deposit a number immediately to ax, ax is 0123,

Thank you for your reply,
The B8 is fixed? If the repeat orders, will appear again B8?

CodePudding user response:

B8 specific still should explain the domain, 1011 w RRR will immediately mov to register accordingly, want to know or see the coding part,
Repeat the mov ax, immediately instruction, is a B8 will appear again,