Stm32 softirqs open failure is why?


In A timing interruption of TIM's open soft interrupt A, will trigger again in the soft interrupt A TIM execution, so the cycle, verification OK, assume that this is the first set of

Again the same set up the second group, a second set of separate operation, the operation OK
But both groups run at the same time, can appear midway through the second group of soft open failed

Note: timing interruption of TIM's priority is higher than soft interrupt priority, each set of the same timer interrupt priority, each set of soft interrupt priority is the same