Python thread mutex-CodePudding

If the lock in the code mark 1, 4, the final result is the main function, 2, 3 in lock, the main function the way to the output,
I also sleep 2 s before the final output, this phenomenon is what reason, (just contact, the hope can say the detailed point, thank you)

 
The import threading 
The import time 


Def test1 (temp) : 
Global g_nums 
# lock 1 
 -- -- -- -- --# mutex. Acquire () 
For I in range (temp) : 
# print (" -- -- -- -- - the gums={} - ", g_nums) 
Lock - # 2 
Mutex. Acquire () 
G_nums +=1 
Mutex. Release () 
# print (" -- -- -- -- -- - the test1 -- -- -- -- -- \ n ") 
# mutex. Release () 
Print (" -- -- -- -- -- in test1 g_num {}, {} ". The format (g_nums, time ctime ())) 


Def test2 (temp) : 
Global g_nums 
Lock - # 3 
# mutex. Acquire () 
For I in range (temp) : 
# print (" -- -- -- -- - the gums={} - ", g_nums) 
Lock - # 4 
Mutex. Acquire () 
G_nums +=1 
Mutex. Release () 
# print (" -- -- -- -- -- - the test2 -- -- -- -- -- ") 
# mutex. Release () 
Print (" -- -- -- -- - in the test2 g_num {} - {} ". The format (g_nums, time ctime ())) 


G_nums=0 
Nums=10000000 
Mutex=threading. The Lock () # create a mutex 

Def the main () : 
T1=threading. Thread (target=test1, args=(nums,)) 
T2=threading. Thread (target=test2, args=(nums,)) 

T1. The start () 
T2. The start () 
Time. Sleep (2) 

Print (" -- -- -- -- -- in the main g_num {}, {} ". The format (g_nums, time ctime ())) 
If __name__=="__main__" : 
The main ()