"What is the output side parallel resistor R33 role? Can someone please answer it for me? Thank you very much!

CodePudding user response:

When the electricity for C41 fast discharge,

CodePudding user response:

Dummy load, when no load for C41 discharge passage, and not in general, there is no problem

CodePudding user response:

Can be removed, chip built a similar resistance, closing is used to provide a load release circuit,
An internal
OUT A2 1
5 O230 - Ω (typical) pull down resistor prevents a charge remaining on VOUT
When the regulator is in the shutdown mode (VEN low).

CodePudding user response:

Accelerate the capacitor discharge, if the voltage to the mV level without C41 discharge special slow, before the use of a chip is due to the slow capacitive discharge chip out bugs,

CodePudding user response:

To learn! Hardware error is!

CodePudding user response:

Wouldn't it be great power consumption

CodePudding user response:

Dummy load capacitance is small behind you, can take away

CodePudding user response:

1, this "light also can stable work, should not be set in order to provide the minimum output current;
2, internal resistance by EN signal control in power supply under normal circumstances, when the hard power need external pulldown resistor to provide discharge circuit (may need to meet the timing requirements), to combine the load circuit is clear;

CodePudding user response:

Inside there should be a capacitance,

CodePudding user response:

Dummy load, usually don't have to add

CodePudding user response:

Main functions are as follows:
1. Need to restart when power cuts, such as load can be quickly dropped the load capacitance of the power drain,
2. To prevent the no-load power instability, a lot of "no such problem,
The downside:
Increase the power consumption and fever,

CodePudding user response:

The minimum load requirements

CodePudding user response:

Don't recommend this way of connection, if there is power to discharge, can on the output side parallel schottky diode or increase the analog switch to control the discharge circuit, so that can reduce the power consumption during normal work,

CodePudding user response:

Dummy load by changing along the steep to control on time,

CodePudding user response:

Some "internal resistance, the output in the performance of small load, voltage control, internal without resistance, small load voltage will be on the high side,

CodePudding user response:

Generally don't have to add, no-load test is a plus

CodePudding user response:

Generally useless,

CodePudding user response:

This is generally do not add

CodePudding user response:

Rapid discharge

CodePudding user response:

For the capacitor discharge power

CodePudding user response:

Dummy load, generally if they begin to work, if the load is light, will lead to high voltage wave;
The other speed under the electricity, because of remove input, output current voltage, can lead to internal device reverse breakdown,

CodePudding user response:

This single let everyone is confused "power supply circuit, the solution can be a result -- -- -- -- -- -- -- that is the resistance is gild the lily, do more harm than good, but I don't think there is a hardware engineer so brainwashed and a harmful load, the truth is: this is an absorption resistance, may be in the later stage circuit must be from IO small irrigation current of high voltage source, in order not to let the current lifting MCU power supply voltage, cause unnecessary interference or damage to the device, take the cheapest compromise,

CodePudding user response:

This should be placed after the terminal voltage overshoot, if rapid fluctuations in front 5 V voltage, 3.3 V output will be very unstable, sometimes would rush to 4 V voltage, can produce damage to the back-end components of IC, so under the condition of without considering the power consumption, and the resistance is reduced load, is "discharge speed, voltage fluctuation is not very intense,

CodePudding user response:

Can be removed, keep up with the power sequence

CodePudding user response:

Power, discharge channel, to prevent the electrical time is too long lead to failure

CodePudding user response:

From the network label is for WIFI for 3.3 V voltage, 220 r obviously false load, avoiding the rapid switch, WIFI and voltage of 3.3 V, affect the WIFI driver,
Hello everyone, the hardware technical tencent QQ group: 907555048, more experts, welcome,

CodePudding user response:

refer to the second floor worldy response:

dummy load, when no load for C41 discharge channel, without no problem commonly

bingo

CodePudding user response:

Generally doesn't do anything, unless there are too many capacitance inductance, peripheral circuit in order to discharge rapidly,

CodePudding user response:

Original factory to provide application and there is no resistance,