How to use Python-CodePudding

Seven security personnel of a company: zhao, money, sun, lee, zhou, wu, Chen, because the job needs to dwell system, a day off each week, and let each person chooses in advance oneself think right day off, please prepare a program that prints were rested all possible solutions, certainly must make everyone satisfied, such as choice of each day of rest is as follows: zhao: on Tuesday, Thursday money: Monday, Saturday: sun li on Sunday: on Friday week: Monday, Wednesday, Thursday, Saturday, wu: Tuesday, Friday Chen: Wednesday, Saturday, Sunday,

CodePudding user response:

 import itertools as it 
The import copy 

TB=[' on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday,] 
D={' zhao: [' Tuesday ', 'Thursday], 
'money: [' Monday', 'Saturday], 
On Wednesday, 'sun' : [' ' 'Sunday], 
'lee' : [' Friday], 
'week' : [' Monday ', 'on Thursday,' Saturday], 
"Wu" : [' Tuesday ', 'Friday], 
On Wednesday, 'Chen' : [' ' 'on Saturday', 'Sunday], 
} 

The index=0 
Key='
For k, v in d.i tems () : 
If the index & gt; 0: 
Cur=it. The product (cur, v) 
CPU=copy. The copy (cur) 
If the index & gt; 1: 
CPU=[the list (I [0]) + [I [1]] for I in cup] 
Cur=cup 
The key +=k 
The else: 
Cur=v 
Key=k 

Index +=1 

For I in cur: 
If len (set (I))==7: 
Res=[key [i.i ndex (_)] for _ in TB] 
Print (res)

CodePudding user response:

refer to the second floor chuifengde response:

 import itertools as it 
The import copy 

TB=[' on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday,] 
D={' zhao: [' Tuesday ', 'Thursday], 
'money: [' Monday', 'Saturday], 
On Wednesday, 'sun' : [' ' 'Sunday], 
'lee' : [' Friday], 
'week' : [' Monday ', 'on Thursday,' Saturday], 
"Wu" : [' Tuesday ', 'Friday], 
On Wednesday, 'Chen' : [' ' 'on Saturday', 'Sunday], 
} 

The index=0 
Key='
For k, v in d.i tems () : 
If the index & gt; 0: 
Cur=it. The product (cur, v) 
CPU=copy. The copy (cur) 
If the index & gt; 1: 
CPU=[the list (I [0]) + [I [1]] for I in cup] 
Cur=cup 
The key +=k 
The else: 
Cur=v 
Key=k 

Index +=1 

For I in cur: 
If len (set (I))==7: 
Res=[key [i.i ndex (_)] for _ in TB] 
Print (res)

Good as you!

CodePudding user response:

refer to the second floor chuifengde response:

 import itertools as it 
The import copy 

TB=[' on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday,] 
D={' zhao: [' Tuesday ', 'Thursday], 
'money: [' Monday', 'Saturday], 
On Wednesday, 'sun' : [' ' 'Sunday], 
'lee' : [' Friday], 
'week' : [' Monday ', 'on Thursday,' Saturday], 
"Wu" : [' Tuesday ', 'Friday], 
On Wednesday, 'Chen' : [' ' 'on Saturday', 'Sunday], 
} 

The index=0 
Key='
For k, v in d.i tems () : 
If the index & gt; 0: 
Cur=it. The product (cur, v) 
CPU=copy. The copy (cur) 
If the index & gt; 1: 
CPU=[the list (I [0]) + [I [1]] for I in cup] 
Cur=cup 
The key +=k 
The else: 
Cur=v 
Key=k 

Index +=1 

For I in cur: 
If len (set (I))==7: 
Res=[key [i.i ndex (_)] for _ in TB] 
Print (res)

Thank you, thank you very much