The idea is to get the sum based on the column names that are
between 01/01/2021
and 01/08/2021
:
# define rank parameters {start-end}
first_date <- format(Sys.Date(), "01/01/%Y")
actual_date <- format(Sys.Date() %m-% months(1), "01/%m/%Y")
# get the sum of the rows between first_date and actual_date
df$ytd<- rowSums(df[as.character(seq(first_date,
actual_date))])
However, when applied the next error arises:
Error in seq.default(first_date, to_date) : 'from' must be a finite number
Expected output is a new column that takes the sum of the rows between the specified rank.
data
df <- structure(list(country = c("Mexico", "Mexico", "Mexico", "Mexico"
), `01/01/2021` = c(12, 23, 13, 12), `01/02/2021` = c(12, 23,
13, 12), `01/03/2021` = c(12, 23, 13, 12), `01/04/2021` = c(12,
23, 13, 12), `01/05/2021` = c(12, 23, 13, 12), `01/06/2021` = c(12,
23, 13, 12), `01/07/2021` = c(12, 23, 13, 12), `01/08/2021` = c(12,
23, 13, 12), `01/09/2021` = c(12, 23, 13, 12), `01/10/2021` = c(12,
23, 13, 12), `01/11/2021` = c(12, 23, 13, 12), `01/12/2021` = c(12,
23, 13, 12)), row.names = c(NA, -4L), class = c("tbl_df", "tbl",
"data.frame"))
How could I properly apply a function to get this output?
CodePudding user response:
The format
and seq
don't work i.e. seq
expects a Date
class whereas the format
is a character
class. Instead, make use of the range operator in across
or select
library(dplyr)
out <- df %>%
mutate(ytd = rowSums(across(all_of(first_date):all_of(actual_date))))
-output
> out$ytd
[1] 96 184 104 96
CodePudding user response:
A base R approach using match
-
df$ytd <- rowSums(df[match(first_date, names(df)):match(actual_date, names(df))])
df$ytd
#[1] 96 184 104 96