How can I filter an array of objects, which itself has an array, by a filter by array, where all the items in the filter by array are found in the objects array?

It might be easier to explain with an example:

const data = [
    {user: 'bob', favoriteThings: ['cats', 'dogs', 'movies']},
    {user: 'sally', favoriteThings: ['cats', 'movies', 'trees']},
]

const filterByFavs = ['cats', 'trees']

// result should only include [{user: 'sally', favoriteThings: ['cats', 'movies', 'trees']}]
// if filterByFavs is ['cats'], then both users are returned. 
// favoriteThings has to have all the items from filterByFavs in order for the filter to apply.     

In the above snipped, I am trying to filter the data so that the result only includes objects where all the items in filterByFavs are found in favoriteThings.

I tried to solve this with both reduce and filter and cant seem to get the desired result.

let out = data.filter((fav) => {
    return (
        fav.favoriteThings.filter((tag) => {
            return !filterByFavs.includes(tag);
        })
    );
});

let a = data.reduce((acc, fav) => {
    let favs = fav.favoriteThings;
    let allExists = favs.filter((tag) => !filterByFavs.includes(tag.text));
    if (allExists) {
        acc.push(fav);
        return acc;
    }
    return acc;
}, []);

The issue I am facing in my logic is I can filter fine when filterByFavs only has one item, but not when it has multiple.

CodePudding user response：

Check that .every one of the items to find is included in the other array being iterated over.

const data = [
    {user: 'bob', favoriteThings: ['cats', 'dogs', 'movies']},
    {user: 'sally', favoriteThings: ['cats', 'movies', 'trees']},
];
const filterByFavs = ['cats', 'trees'];
const result = data.filter(
  obj => filterByFavs.every(str => obj.favoriteThings.includes(str))
);
console.log(result);