I'm trying to remove Dutch phone numbers from a string via a regular expression. The phone numbers to remove can contain spaces, and dashes and the country code.
These are typically used formats to be detected:
06-12345678
0612345678
0612345678
0101234567
010-1234567
010 1234567
010 12 34 567
010 12 34567
010 1234 567
31612345678
0031123456789
So far I have: ^(?:0|(?:\ |00) ?31 ?)(?:(?:[1-9] ?(?:[0-9] ?){8})|(?:6 ?-? ?[1-9] ?(?:[0-9] ?){7})|(?:[1,2,3,4,5,7,8,9]\d ?-? ?[1-9] ?(?:[0-9] ?){6})|(?:[1,2,3,4,5,7,8,9]\d{2} ?-? ?[1-9] ?(?:[0-9] ?){5}))$
This works perfect when phone numbers are on a separate line but NOT when they're inline like so:
this is a list of numbers inline 06-12345678 gggf0612345678 06 12345678 0101234567 010-1234567 dfgfdg010 1234567
Test it here: https://regex101.com/r/jOEFwS/2
I've checked here, but that is for US phone numbers:
How can I change my expression to capture inline?
CodePudding user response:
You need to remove ^
from the start and $
at the end.
Some more info: In regex101 you have the m flag, which makes ^ and $ line based, without it ^ is start of string and $ is end of string.