Trying to understand operands in python.

8/2(2 2) gave the following error:

TypeError Traceback (most recent call last)
<ipython-input-12-8949a58e2cfa> in <module>
----> 1 8/2(2   2)

TypeError: 'int' object is not callable.

Trying to do this like this then using sum() then as python dictionary then in numpy.

CodePudding user response：

Python doesn't support implicit multiplication. When Python tries to run 2(2 2), it tries to call the numeric literal 2 as a function, passing 2 2 as an argument to it. You need to use * between things you want to multiply.

CodePudding user response：

There is no operator between the 2 and the ( - human math assumes a multiplication here but a computer does not.

The parser sees 2(...) - which is interpreted as a function with the name 2 and a parameter.

Since there is no default function with that name and there is no def 2(x) you get that error message.

Additionally 2 is not a vaild function name in python.

CodePudding user response：

Python doesn't work like normal maths. 2(2 2) will not be executed as 2×4. Instead, 2 will be treated as a function, which is not callable (your error message) . To do that, you've to put operator between 2 and (2 2). Try putting a * between 2 and (2 2). Your expression would be 8/2*(2 2)