Search duplicates in php mysql database in same table from2 columns-CodePudding

I have 2 columns in the table and I want to search for duplicates for every row from first column in all column 2. So I want to find if every row in column 1 exist in all column 2. I specify that my table is big, have 3 millions rows. my table name is bigquerry and have 2 columns : id1, and id2

CodePudding user response：

Use a JOIN to link the table back on itself, and JOIN on the ID fields.

Assuming a simple table like this:

id	id1	id2
1	A	B
2	C	D
3	E	F
4	G	A
5	H	C
6	I	A
7	J	A
8	K	C
9	L	F

You can extract the duplicates with this query:

select a.id, a.id1, b.id, b.id2 from duplicates a join (select id, id2 from duplicates) b on a.id1 = b.id2;

Output:

id	id1	id	id2
1	A	4	A
1	A	6	A
1	A	7	A
2	C	5	C
2	C	8	C

Note Make sure you have indexed the id2 column or this could take a very long time.

Demo: https://www.db-fiddle.com/f/fbZiyxa7fSzZFDhm9BS32L/1

CodePudding user response：

Here you go

<?php
//set time limit to indefinite to parse the 3m rows
set_time_limit(0);

$conn = new mysqli("localhost", "username", "password", "db_name");
$id1list = $conn->query("SELECT id1 FROM `bigquery`");

//loop through all id1 returned by the query
while($r = mysqli_fetch_assoc($id1list)) {
    $id1 = $r['id1'];
    
    //get the count of id2 which are equal to the current id1
    $id2count = $conn->query("SELECT count(id2) FROM `bigquery` WHERE id2='$id1'");
    $count = mysqli_fetch_array($id2count)[0];
    
    //print if count is greater than 0 (exists in id2)
    if($count>0){
        echo "$id1 is repeated $count times. <br>";
    }
}
?>