This Regex works fine in Chrome and Firefox

let regexp = new RegExp(`^${searchTerm}|(?<=\\s)${searchTerm}`, 'gi')

but unfortunately Safari complains

SyntaxError: Invalid regular expression: invalid group specifier name

It looks like Safari doesn't support the lookbehind, but how can I transform it so I get the indices of the searchTerm without the whitespaces?

let regexp = new RegExp(`^${searchTerm}|(?<=\\s)${searchTerm}`, 'gi')
let matchIndices = [...string.matchAll(regexp)].map(match => match.index);

matchIndices.forEach(index => {
   ...
});

CodePudding user response：

You can use a regex like /(^|\s)word/gi and if Group 1 does not match a whitespace, collect the match index, otherwise, match index 1 value:

let searchTerm = "foo"
let string = "foo fooo,foo"

let regexp = new RegExp(`(^|\\s)${searchTerm}`, 'gi')
var matchIndices = [], m;
while(m = regexp.exec(string)) {
  if (m[1] === "") {
    matchIndices.push(m.index)
  } else {
    matchIndices.push(m.index 1)
  }
}

matchIndices.forEach(index => {
   console.log(index)
});

<iframe name="sif1" sandbox="allow-forms allow-modals allow-scripts" frameborder="0"></iframe>