Split string and still keep the delimiter-CodePudding

I have a string of code like this:

replace [IntType]
import TYPE [libc_to_basic_type_entry*]

Now I want to split them into arrays by using Python regex like this:

["replace", "[", "IntType", "]"]
["import", "TYPE", "[", "libc_to_basic_type_entry, "*", "]"]

What is the best way to do this? Thanks.

At first, I try to do simple string.split("[") and keep looping over the string to split with the other characters. But i found that this way is not effective, so I would like to ask for help by using regex.

CodePudding user response：

You may use this regex:

\s*(\w |[^\w\s])\s*

RegEx Details:

\s*: Match 0 or more whitespaces
(: Start capture group
- \w : Match 1 word characters
- |: OR
- [^\w\s]: Match a character that is not a word or whitespace character
): End capture group
\s*: Match 0 or more whitespaces

Code:

s = 'import TYPE [libc_to_basic_type_entry*]'
print (re.findall(r'\s*(\w |[^\w\s])\s*', s))

Output:

['import', 'TYPE', '[', 'libc_to_basic_type_entry', '*', ']']