React: how to fire useeffect using context variable as dependency?-CodePudding

I was trying to figure out how to fire a useEffect when its dependency is a useContext variable. My Context has an "update" variable, which at one point changes, but the effect isn't fired.

import { useEffect, useState, useContext } from "react"
import context from "./Context"

const Layout = () => {
    const ctx = useContext(context)
    const [updateState, setUpdateState] = useState(ctx.update)

    useEffect(() => {
        console.log("effect fired")
    }, [updateState])

    return (
        <div>
        </div>
    )
}

export default Layout

I tested whether the issue was my context "update" variable not changing, but it does. I will appreciate any help with this.

CodePudding user response：

Your problem is that you used useState. This in effect memoized/froze the value of updateState, to the first run of this component.

You see useState takes a single arg (default value). Which is only used on the first render of the component, to populate updateState. When ctx.update changes, useState already has a default to set updateState to, so it is ignored.

Instead, you can remove useState completely...

import { useEffect, useState, useContext } from "react"
import context from "./Context"

const Layout = () => {
    const { update as updateState } = useContext(context);
    // Notice I have removed the useState.

    useEffect(() => {
        console.log("effect fired")
    }, [updateState])

    return (
        <div>
        </div>
    )
}

export default Layout